Date: 7 February 2012 11:48
Dear colleagues,
We have solved the crystal structure of a human enzyme. The pKa of a catalytically critical aspartic acid has increased to 6.44. It is hydrogen bonded (2.8 Angstroms) to a water molecule that is supposed to donate a proton during the catalysis. Can anybody help me a) interpret the significance of this increase in pKa of the aspartic acid from 3.8 to 6.44 in context with the catalysis? Is this advantageous or detrimental? b) How is pKa related to an amino acids' ability to force a water molecule to donate a proton? c) At pH 7.4, the aspartic acid would be de-protonated irrespective of whether the pKa is 3.8 or 6.44; isn't that true? d) Have similar increase in pKa values observed for aspartic acids before? I would be grateful if anybody could explain or comment on the above queries.
Deepak Oswal
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From: Clement Angkawidjaja
Assuming that you have done the necessary things to measure the pKr of that particular Asp, I would say that the increase is advantageous for your enzyme. Enzyme catalysis often involves very subtle changes on the ionization state of the active site. But you need to be very careful in proposing a catalysis mechanism. Are you sure that the water donates a proton? Was your resolution high enough to observe it? How did you measure that pKr, by the way? I would say that the dominant fraction of Asp is deprotonated. But as you can see in the papers below, the pKr of Asp can vary from 0.5 to 9.2 in folded proteins. there are some papers by Nick Pace's group:
http://www.ncbi.nlm.nih.gov/pmc/articles/PMC2708032/?tool=pubmed
http://www.ncbi.nlm.nih.gov/pmc/articles/PMC2679426/?tool=pubmed
http://www.sciencedirect.com/science/article/pii/S002228360600934X
Cheers,
Clement
--
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From: Xiaodi Yu
I think it is common for the residues which participate catalysis to have a Pka deviated from the reality pKa value especially for acid/base catalysis (acid base titration assay can help you to figure out the way of catalysis). Usually the pKa values of these kind of critical residues are affected by their local environment and this character is related to the enzyme's working mechanism.
I am sorry that I am not professional in enzyme, I cannot answer your questions for each questions.
Yu Xiaodi
From: Roger Rowlett
I think it is unusual for water to act as a general acid (the pKa of water is 14-15, depending on how you calculate it), but if that is the case and there is compelling evidence that water is the proton donor in your reaction, it would be necessary for aspartic acid to be in its protonated form in order to assist a water-mediated protonation event. Raising the pKa of aspartic acid would allow a larger fraction of it to be in its protonated state at physiologically relevant pH values, although it would reduce the intrinsic effectiveness of Asp as a general acid. There should be a significant thermodynamic and kinetic advantage in having Asp participate directly in a general acid catalyzed reaction, rather than through a water molecule.
Cheers,
_______________________________________
Roger S. Rowlett
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From: Kevin Jin
As we know, the pKa of water is 15.7. Under pH 7.0, its protonation
should be 50/50.
In this case, we may need to consider water in two formats:
H2O vs. H3O+
When we say water as acid, it usually stands for H3O+ in chemistry. In
chemical equation, H+ represents H3O+.
In enzyme catalysis, water as a general acid sounds reasonable under
pH 7.0. In some famous paper, water has been concluded as the general
base (pKa 15.7) to deprotonate an alpha hydrogen (pKa ~ 22) or a
hydrogen from a sp3 hybridized carbon (pKa ~36). This logic may need
to be reconsidered.
.
Recently, I have read papers for pKa perturbation. I am also
interested in the general base of Asp and Glu in enzyme catalysis.
I will be very happy to read your paper in the future.
Regards,
Kevin Jin
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From: Fischmann, Thierry
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From: Fischmann, Thierry
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From: Christian Roth
Hi,
you may also look into the papers of John A. Gerlt, who did a lot on
protonabtraction reactions and the theory behind this. Esspecially the pKa
disturbance and the match to the pkA of the substrate of the reaction.
Best Wishes
Christian
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From: Hong Zhang
Is the water molecule in question coordinated to any other group(s)?
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From: Kevin Jin
Maybe you would also be interested in
http://www.jinkai.org/AAD_history.html
Regards,
Kevin
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From: Francisco Hernandez-Guzman
Hi Deepak,
With regards observed pKa shifts, Prof. Ondrechen from Northeastern University has had a long interest in this field.
http://www.northeastern.edu/org/wp/
Under the computational tools that she has developed a program called THEMATICS that allows you to predict the pka of titratable amino acids and she has been able to predict shifts. Though the server seems to be down at this point, here is the reference: Y. Wei, J. Ko, L.F. Murga, and M.J. Ondrechen, BMC Bioinformatics 8:119, (2007)
From the commercial side, Dr. Spassov from Accelrys has also been working on tools that predict protein ionization. In his work, he has also been able to predict significant pka shifts for functionally relevant residues.
http://www.ncbi.nlm.nih.gov/pmc/articles/PMC2578799/
Cheers,
Francisco
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From: Zachary Wood
Hi Kevin,
Hate to point this out, but under pH 7.0, the protonation state of water is not 50:50, and it is not a good acid. The H30+ concentration of pure water is 10^-7 Molar. In pure water (assuming 55.5 M) only 1:555,000,000 water molecules is in the protonated, charged state (H3O+). This is why when an enzyme uses water in its mechanism as a nucleophile, base, or acid, there is usually an acid/base catalyst or metal that protonates or deprotonates the water to 'activate it'.
Best regards,
Z
***********************************************
Zachary A. Wood, Ph.D.
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From: Kevin Jin
Oops, It should be: [H3O+]/[OH-]= 50/50
Kw = [H3O+][OH-],
pH = pKa +log ([OH-]/[H2O])
H3O+ concentration of pure water is 10^-7 mol/L
total H+ = 55.5M * 10^-7 = 5.55* 10^-6 mole. Is this right?
Regards,
Kevin
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From: Roger Rowlett
So at pH 7.0, you have 10^-7 M each at equilibrium no matter how you slice it or whatever else is in solution. If equilibrium [H3O+] goes up [OH-] goes down commensurately.
The "pKa" of water as an acid is based on Kw and water's effective concentration of 55 M in pure water. This "pKa" is used to compare the instrinsic acidity of water to other weak acids. Water is an exceptionally weak acid or base.
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From: Horacio Botti
Dear Deepak
Alternatively, please also consider that the higher the pKa the higher the nucleophilicity of the residue/group (higher SN2 reactivity or affinity with electrophiles, like H+, perhaps the substrate of your enzyme..?, etc) .
best
Horacio
--
Horacio Botti
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From: Horacio Botti
Dear all,
for further discussion
I believe that using the "0-14" pH scale assumes water activity of pure water, something that is surely not matched in the surface or pocket of a protein, so keeping this in mind I always prefer to speak about apparent pKa of a group if talking about a non solvent-exposed group.
Horacio
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From: Edward A. Berry
And note that Kw, like other physical constants, depends on temperature,
ionic strength, etc. Therefore neutrality, defined as the concentration
where H+ = OH- , which is half of pKw*, is not exactly 7.0, but varies.
A lot of students come out of first-year chemistry with the idea that
pH 7.0000 is by definition neutral.
(*That is using the old Kw definition where {H2O} is taken as 1)
The pK at 14 (or 14+log(55)) is for H2O <-> OH-, H+
i.e. pH where H2O = OH-
The pK at 0 (or -log 55)) is for H3O+ <-> H2O, H+
i.e. pH ph when H3O+ = H2O
But isn't H+ = H30? then when H3O+ = H2O, [H3O] = 55/2,
pH would be -log (55/2)
pH is log of "activity of water, or whatever the glass electrode measure.
Or- assuming [H2O] always unity, when H2O = H3O+, H3O+ = 1, pH=0
assuming [H2O] always 55, extrapolate to where H3O+ = H2O while keeping H20=55,
then pH would be -log 55
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